all I'm asking for is the proper formula to solve the following.a spherical area for an auxiliary water tank is set aside in a buildingWhen full, the sphere could contain exactly 1200 cubic metres of waterHowever, at the last minute the job is given ti a company that only builds water tanks in the shape of regular icosahedrons constructed out of 3 centimetre-thick, low-grade aluminum.If the icosahedron tank is the largest it can possibly be while still fitting within the spherical area, what is the volume of the tank in cubic metres?again while I don't mind being given the answer all I really require is the proper formula to solve this.
get your gran to do it old people are awesome at knitting
if you are loom knitting on a round loom like the Knifty Knitter, you need to use 2 strands of medium kniting worsted yarn like red heart in order for the hat to be done correctlylooms are large gague, meant for bulky yarnmost people have trouble finding it, so make your own bulky with 2 strands held as one.of course, if you can get bulky, use it.
Most of the plastic knitting loom pegs are the equivalent of a Size 10 or 11 knitting needlePick your yarn accordinglyUsing two strands of knitting worsted should help.
relevant formulae in source linkradius of sphere R 6.5922 m can be found from known volume 1200 cu.m length of edge of inscribed icosahedron is a1 R/0.95105656.931456 m the radius of an inscribed sphere (tangent to a face) is r a1x0.7557613 5.238526 mfrom this we subtract the 3cm thickness of the aluminium plate, giving a radius for the inscribed sphere of 5.208526 mthe edge length corresponding to this is a25.208526/0.75576136.89176 m finally the volume of the inner icosahedron is V2.18169499a2^3714.142 cu.m alternatively we could subtract 3cm from the radius of the outer icosahedron, but this will give a less accurate answerso now incribed radius: R 6.5922 -0.03 65622 m and a R/0.95105651 6.89991 mV2.18169499a^3716.678 cu.m
