Brass is a mixture of copper and zinc. Parts of a brass bar containing 60% zinc and a brass block containing 40% zinc and melted together. If the resulting 400 kg mixture is 51% zinc, how much of the bar and the block were used?
Brass Bar used (400 kg mixture)(51 kg zinc/100 kg mixture)(100 kg Brass Bar/60 kg zinc) 340 kg Brass Bar Brass Block used 400 - 340 60 kg Brass Block
this is like cheap stoichiometry. set up a picket fence equation. if u dont know what that is, learn chem.
Let brass bar used be b grams so block brass used (400 – x) zinc in x gram x × 60/100 0.6x gm zinc in (400 – x) gram (400 – x) × 40/100 160 – 0.4 gm zinc in 400 gram 400 × 51/100 204 gm zinc balnce 0.6x + 160 – 0.4x 204 0.2x 44 x 220 gm of 60% bar and 400 – 220 180 gm of 40% block --------
