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Question:

Need help with a molarity question.?

What is the molarity of a solution made by dissolving 40.283 g of aluminum sulfate, Al2(SO4)3, in water and diluting with water to 250.0 mL total?

Answer:

Without calculating your answer looks OK - usually written as Al(NO2)3 Aluminium (lll) nitrite.
Empirical formula are formula that express the climate in a substance in terms of the smallest finished style ratio of the climatesome empirical formula additionally are the surely molecular formula like the formula for water - H2OThe compound is composed of two hydrogen atoms and a million oxygen atom, the formula is the two empirical (lowest finished style ratio) and moleculardifferent formula, like numerous carbohydrates, have the empirical formula CH2OThis expression tells us that for each C, there'll 2 H and an OGlucose, a shopper-friendly carbohydrate has the molecular formula C6H12O6be conscious that if we divide via by the final consumer-friendly multiple (6) we get CH2O - the empirical formulai do no longer comprehend what you recommend by clarify the magnitude of prefixesconsidering your different question pertained to formula, i anticipate you're relating the common naming device for molecular compounds (those with covalent bonds) wherein conventional Greek prefixes (mono, di, tri, tetra, penta, hexa, hepta, octa, nona, and deca) are used to precise how lots of a area seem interior the formula for the substancecase in point CO is carbon monoxide, CO2 is carbon dioxide, N2O4 is dinitrogen tetroxide, N2O is dinitrogen monoxideThis naming device isn't the conventional or favourite thank you to call compoundsthe popular nomenclature defined by IUPAC makes use of oxidation states of the useful factor expressed as Roman numerals interior the callThe IUPAC call for N2O4 is nitrogen(IV) oxide, the IUPAC call for N2O is nitrogen(I) oxide, CO2 is carbon(IV) oxide, CuCl2 is copper(II) chloride.
The compound would be Al(NO2)3, aluminum nitriteIt is not named using the Stock systemCan't help you on round to the half.
by definitionmolarity moles solute / L of solution from the problem statementyou have g solute / mL of solution right? and all you need to do is convert(40.283g / 250.0mL) x (1 mol / 342.15g) x (1000mL / 1L) 0.4709 M and yes that has 4 sig figs because as this is all multiplication / division and the factor with the lowest number of sig figs (250.0 with 4) limits the answer to 4 if you can follow Mr Park(s)'s (the dude calling himself chemteam) logic he's saying this since M moles / volume M x V moles and since molar mass mass / mole mass / molar mass moles so that M x V mass / molar mass solving for M M mass / molar mass / Volume I think that's a bit round about and takes to much memorizationnow if you look at my equation, (40.283g / 250.0mL) x (1 mol / 342.15g) x (1000mL / 1L) 0.4709 M When I used dimensional analysisyou can see mass / Volume / molar masswith a conversion from mL to L same thing as chemteam's BUT (1) I didn't need to pull M x V moles moles mass / molar mass .out of the recesses of my brain (2) I use the same method EVER TIME to solve nearly all gen chemistry problems .start with the FROM on the left convert to the right to get the units I want .and that consistency makes me (and you if you do this) highly accurate and very fast! (3) tracking sig figs is EASY (4) the calcs are easy to enter in your calculator and double check .40.283 / 250.0 / 342.15 x 1000 (5) there is built in error check.make sure the units cancel properly .double check all your conversion factors (6) I can readily demonstrate my problem solving strategy to teachersi.ethey'll understand the work yes both answers ended up the samebut DA is a much more powerful method.

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