My tracer face us this question and I am in desperate need of an intelligent mind!!! Here is the problem: A white cylindrical silo has a diameter of 30 feet and a height of 80 feet. A red stripe with a horizontal width of 3 feet is painted on the silo, making 2 complete revolutions around it. What is the area of the stripe in square feet? I got so far into finding the area of the whole cilo, but not sure where to go from there... THANKS FOR READING!
You take the surface area of the silo (without the top and bottom), but you use 3 instead of 80. 2pirh 2pi(15)(3) = 90pi. Multiply that by 2. 180 pi. I hope this information was very helpful.
you do not need the area you need the circumference silo diameter is 30 feet radius is 15 c=2pi(r) c=2pi(15) c=30pi to revolutions 60pi stripe has 3 foot width [the 'triangle' at the top will offset the 'triangle' at the bottom 3(60pi) 180pi square feet 565.2 square feet [more or less] :D
Actually, you don't even need the area of the silo. If it's being painted horizontally, you have a height of 3 Feet. With a diameter of 30 feet. You'd need the circumference which is 2Pi(r). Or 30(Pi) = 94.2 Feet. So the area around being painted would be 94.2 Feet x 3 = 282.6 for 1 revolution. Since you're painting it in 2 complete revolutions, you're painting the same spot twice. So it's just 282.6 Feet.
