How many kilograms of limestone should be added for every kilogram of iron ore processed in a blast furnace if the limestone is 93.80% pure and the iron ore contains 12.00% SiO2 by mass? (Note: SiO2(s) + CaCO3(s) → CaSiO3(s) + CO2(g))
SiO2(s) + CaCO3(s) → CaSiO3(s) + CO2(g)) The coefficients in the balanced equation indicate the number of moles of the products formed from the number of moles of the reactants. 1 mole of SiO2 reacts with 1 mole of CaCO3 to produce 1 mole of CaSIO3 and 1 mole of CO2. Mass of 1 mole of SiO2 28.1 + 32 60.1 g Mass of 1 mole of CaCO3 40.1 + 12 + 48 100.1 g 60.1 grams of SiO2 will completely react with 100.1 grams of CaCO3. Now you need to determine the mass of iron ore which contains 60.1 grams of SiO2, and the mass of limestone which contains 100.1 grams of CaCO3. Mass of SiO2 / Mass of iron ore 0.12 Mass of iron ore Mass SiO2 / 0.12 60.1/0.12 500.83 g Mass of CaCO3 / mass of limestone 0.938 Mass of limestone Mass CaCO3 /0.938 100.1 / 0.938 106.7 g 106.7 grams of limestone reacts with 500.83 grams of iron ore. How many kilograms of limestone should be added for every kilogram of iron ore? Convert masses to kilograms. 1 kilogram 1000 g 0.1067 grams of limestone reacts with 0.50083 grams of iron ore. Set up a proportion. 0.1067 / 0.50083 x / 1 x 0.1067 / 0.50083 0.213 kg of limestone
