I would like to use a 4KW motor as power, its speed is 1440r/min, current 6; 6A, this power through the gearbox speed change, the output speed is 30r/min, if it does not ignore power loss, then what is the power output?,Yes, his power should be constant, so his torque is increasing? About how much?
The power is constant!! Or 4KW?.Power = speed * torqueIf the power loss is not considered, the power is conserved in the mechanical transmission.Because energy is conserved, power = energy / time, so power is conserved
If the power loss is not considered, then what is the output power, then it is still 4 kW?. The driving power has nothing to do with speed. The speed is related to the force distance, the change of the speed and the change of the pull distance.Gear box should show the transmission power, such as transmission power of 86%, indicating input shaft 4KW, then the output is 4KW*0.86=3.44KW.
Irrespective of power lossThe motor output torque is =9550 * power (kw) / rev (RPM) =9550 * 4/1440=26.5 (NM)The transmission output torque is =9550 * 4/30=1273.3 (NM)So the torque is increased by 1273.3-26.5=1246.8 (NM)
