To find the mass percent of dolomite [CaMg(CO3)2] in a soil sample, a geochemist titrates 12.86g of soil with 33.56mL of 0.2516M HCl. What is the mass percent of dolomite in the soil? Answer: 3.027 mass %I cannot understand the steps to solving this. Could you explain to me.
Weite the balanced equation: CaMg(CO3)2 + 4 HCl MgCl2 + CaCl2 + 2 CO2 + 2 H2O 1mol CaMg(CO3)2 will react with 4mol HCl Mol HCl in 33.56mL of 0.2516M HCl 33.56/1000*0.2516 8.44*10^-3 mol HCl The soil will contain (8.44*10^-3) / 4 2.11*10^-3 mol CaMg(CO3)2 Molar mass CaMg(CO3)2 184.4016 g/mol 2.11*10^-3 mol 8.44*10^-3*184.4016 0.389g CaMg(CO3)2 Mass of soil 12.86g % CaMg(CO3)2 0.389/12.86*100 3.027% CaMg(CO3)2
