Okay in chemistry we are doing percent yield of thingsI'm not sure if i'm doing this correctly or not so if those of you who are good at this concept/can do it quickly/easily could you please check over and make sure i got the right answer for this questionI used factor labeling/StoichiometryWhat is the percent yield if 4.65 g of Cu is produced when 1.87 g of aluminum reacts with an excess of copper (II) SulfateGiven:2Al (s) + 3CuSO4 (aq) - Al2(SO4)3 (aq) + 3Cu (s)The answer i got for the percent yield is 39.7% or 40% rounded.
1.87 g of aluminum x(1mole Al/26.98gr).069 mole of Al 53.96g Al produce 190.65g Cu So, theoretically 1.87g of Al should produce 6.61g Cu % yield(actual yield/theoretical yield) x 100 4.65/6.61 x100 70.35% 4.65 g of Cu
