A mine produces an ore that is app 10% iron . How much ore must be mined to produce 73 pounds of iron?
ore has only 10 % iron let amount of ore be x x*(10/100)73 x/1073 x730 so amount of ore to be mined is 730 pounds
If the ore is 10% iron, this means that: quantity of iron 0.10 * quantity of ore Plug your give value into the above equation 73 lb iron 0.10 * lbs of ore solve to get 730 pounds of ore.
