A 47.2 g of iron ore is treated as follows. Theiron in the sample is all converted by a seriesof chemical reactions to Fe2O3. The mass ofFe2O3 is measured to be 13 grams. What wasthe percent iron in the sample of ore?Answer in units of %Please and thanks so much! I‘m sooo stuck on this question, haha.
mass of Fe in Fe2O3 mass of Fe in iron ore mass of Fe in Fe2O3 (13 g Fe2O3 / 159.69 g/mol) x (2 mol of Fe / 1 mol of Fe2O3) x 55.85 g/mol mass of Fe in Fe2O3 4.55 g % Fe in ore (9.09 g / 47.2 g) x 100% 19.27% answer
13g Fe2O3 (1mol/159.69g)(2moles of Fe/1mol of Fe2O3)(55.845g/1mole Fe)(1/47.2g)(100) 19.26% Fe
