A 1:150 transformer has a primary voltage of 4500 V. (a) What is the voltage in the secondary coil? (b) If the transformer consumes 45 W, what are the currents in the primary and secondary coils?
1:150 implies a Voltage Step Up transformer. Hence the secondary voltage is 4500 x 150 675000 V 675 KV. 45 W at 4500 V means Ipri 45 / 4500 1/100 A or 10 mA. Secondary current 10 mA / 150 66.6 uA If they meant a 150:1 transformer the answers would be:- Secondary Voltage 4500 / 150 30 V. Primary Current 45 / 4500 1/100 A or 10 mA AGAIN; Secondary Current 10 mA x 150 1.5 A.
Secondary voltage is 4500*150 If transformer losses are neglected, and a load is assumed in secondary, the load resistance is E^2/P (4500*150)^2/45. Current in secondary 45/(4500*150). Pri current is 150 times current in secondary.
hello walrus, I am Camdus.
