Physics high school. Why does a spring fall to the lowest point and the acceleration a must be greater than the acceleration of gravity g ah. Seek expert
According to the conservation of mechanical energy, the object should be a free fall motion at the upper end of the spring
For small spheres, the energy is conserved from the free fall to the ultimate spring compression equal to the maximum value of XMgX=0.5kX^2 (this formula is obtained by integration, do not know if you have no calculus)Calculate X=2mg/k, then the lowest point is the resultant force of the ball is kX-mg=2mg-mg=mg, in the direction of acceleration, the size is exactly equal to GIf the ball is considered to fall from high, then the energy conservation before it converts the energy of the potential energy into springs is naturally more, and the acceleration of the lowest point ball is greater than g
Is the map tilted?.Look at the picture. It means that a naturally stretched spring is placed vertically and then put a mass of m at zero initial speed.If dropped to the lowest point, the speed of the object v=0, object by the acceleration of gravity g down, if not spring to give it an g greater than or equal to the acceleration, the object will continue to fall, do not conform to the original intention of "low".So the acceleration inside the spring must be greater than or equal to g.
