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Question:

physics transformer output and input question. help?

even though the output voltage of a transformer can be much larger than the input voltage, the power output is nearly the same as the power input.Determine the relationship between the input and output current and the number of turns in the input and output coils.help!!!!!!!!thank you

Answer:

If turns ratio is N, output turns divided by intput turns, then voltage ratio is also N, and current ratio is 1/N For example, a 120 VAC transformer with a 12 volt 10 amp secondary will have a turns ratio of 1/10, a voltage ration of 1/10 (12/120) and a current ratio of 10 (1 amp in primary, 10 amps in secondary) .
Lots of on-line sources to develop transformers based on size of wire, turns, amperage, flux based on the transformers materials. Theory indicates a 1/1 relationship between primary and secondary. Practical uses the properties of the materials/the current and voltage constraints of voltage- breakthrough and the Volt-Amperage capacity of the transformer.
The transformer winding (primary or secondary) with the greatest number of turns has the least current. (The current in the secondary winding) [( the number of turns in the primary winding) / (the number of turns in the secondary winding)] x ( the current in the primary). Of course the primary current in any particular ideal transformer is determined by the load on that transformer. If there is no load then both primary and secondary currents are equal to zero.
just read your text book. lets say we have a transformer with a turns ratio of 10:1 If we apply 20 V on the high voltage side, (the side with the higher turns ratio aka 10:1), on the other side it will have 2 V. This is because of the turns ratio. Lets say that the power input on the high V side is 100W. So the current on the high V side is 100W/20V5 A Assuming ideal transformer with no losses, power in is power out. So on the other side, you will also get 100W. So the current on the low V side is 100W/250 A Basically, going from one side to the other, the V increases and the I decreases to keep the same power on both sides, as according to the turns ratio. I hope that you can figure out how the turns ratio of 10:1 made sense here. I better get best answer for this, lol. But seriously, read the text book, see how the turns are wound see how the electric field makes a magnetic field, which makes the electric field, etc.

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