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Question:

please help.....Copper Analysis by Spectroscopy?

You are given a solid UNKNOWN, containing copper, weighing........ 1.6595 g. You dissolve this in concentrated Nitric Acid, HNO3, transfer quantitatively to a 100 mL volumetric flask, add the required amount of Ammonia, NH3, dilute to volume and mix thoroughly.This resulting solution is too concentrated and the resulting %T measured in the same cuvet and spectrometer as before gave little or no transmission (<10%).You are told to pipet.................... 12.00 mL into a 100 mL volumetric flask, add the required amount of ammonia, dilute to volume and mix.Spectroscopic measurement of this solution gave %T... 38.5 %CALCULATE:The Percent of copper in the original solid UNKNOWN..._________%Cu

Answer:

Part of Kluiber's prelab I presume... l)absorbance of diluted solution A=log(blank/sample) A=log(blank/38.5) (fill blank in with your blank %) we'll call the A value here AD (absrobance diluted) for the following problems... m) copper concentration of diluted solution in...M M = AD/average ratio of absorbance you'll find the average ratio of absorbance is g) on the sheet we'll call the M value here CD(concentration diluted) for the following problems... n)copper concentration in original solution...M M=CD[100mL/1000]/[12.00mL/1000]-conver... to liters M=CD(.1L)/.012L we'll call the M value here CO (concentration original) for the following problems... o)% copper in original solution ...%Cu %Cu = ([CO(atomic weight of copper)]/weight of solid unknown)*100 %Cu = ([CO(63.546)]/1.6595)*100 Hope this helps... (this is a duplicate post)
Copper Analysis By Spectroscopy
Thanks a ton! This was INSANELY helpful!!!

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