A horizontal aluminum rod 4.8 cm in diameter projects 5.3 cm from a wallA 1200 kg object is suspended from the end of the rodThe shear modulus of aluminum is 3.0 x 10^10 N/m^2Neglecting the rod's mass, find:(A) The shear stress on the rod(B) The vertical deflection of the end of the rod.The answers are:(A) 6.5 x 10^6 N/m^2 (B) 1.1 x 10^(-5) mbut I don't know how to get these answers, please help me!
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A) The shear stress τ F/A 12009.8/(.048π/4) 6498827 N/m? B) The deflection d Lτ/G .0536498827/3E10 1.148E-5 m This is not a good problem for the study of shear deflection, as the rod will bend as well as well as deflect in shearAlso, for a round rod in shear, the maximum shear stress is actually 4/3 the average stress, which we have calculated here.
