Write the balanced net ionic equation for the reaction between silver (I) nitrate andaluminum chloride.1) 3 Ag+(aq) + 3 Cl-(aq) → 3 AgCl(s)2) Al3+ (aq) + 3 NO3- (aq) → Al(NO3)3(s)3) 3 Ag2+(aq) + Cl-(aq) → AgCl(s)4) Al 2+(aq) + 2 NO3-(aq) → Al(NO3)2(s)5) No precipitate forms.Could you also explain how you got the answer? thx
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parakeets, The answer is (1)The total equation would have been 3AgNO3(aq) + AlCl3(aq) - 3AgCl(s) + Al3+(aq) + 3NO3-The aluminum ion and the nitrate ions do not react, and therefore are spectator ionsThat leaves you with the net equation in (1), as AgCl is quite insoluble and precipitates outJust FYI, nitrate salts are are quite soluble, so it is not (2); (3) is straight-out unbalanced; and (4) there is not enough nitrate to neutralize the aluminum (which should have had a 3+ charge), so it too is unbalancedHope that helped!