A 218-g aluminum calorimeter contains 618 g of water at 19° CA 104-g piece of ice cooled to -19° C is placed in the calorimeter(Assume that the specific heat of ice is always 2.02 kJ/kg · K.)(a) Find the final temperature of the system, assuming no heat is transferred to or from the system(b) A 202-g piece of ice at -19° C is addedHow much ice remains in the system after the system reaches equilibrium?
These are long setups, easy to make mistakes but here goesYou'll need specific heat of aluminum and Latent Heat of Fusion of ice (look it up)Heat energy lost by calorimeter + heat lost by water heat gained by ice to a) go from -19 to zero plus b) melt plus c) warm up as water from xero to Tf 218 (Sal) (19 - Tf) + 618 ( 4.2) (19 - Tf) 104 Lice + 104 (2.02) [0 - (-19)] + 104 (4.2) (Tf - 0) solve for Tf once you put in all the numbers For part b) its the same only you leave out part c) for the iceGood LuckJust work each bit out and write it down as you go along.
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