A 87.7 N sack of grain is hoisted to a storage room 68 m above the ground floor of a grain elevator.How much work was required? What is the potential energy of the sack of grain at this height?The rope being used to lift the sack of grain breaks just as the sack reaches the storage room.What kinetic energy does the sack have just before it strikes the ground floor?
A 87.7 N sack of grain is hoisted to a storage room 68 m above the ground floor of a grain elevator. How much work was required? Work = Fw*h = 87.7*68 = 5,963.6 joule potential energy U = Work = 5,963.6 joule Ek = 1/2mV^2 = 1/2Fw/g*2gh = Fw*h (energy conservation principle) What is the potential energy of the sack of grain at this height? The rope being used to lift the sack of grain breaks just as the sack reaches the storage room. What kinetic energy does the sack have just before it strikes the ground floor?
