I wonder what the formula for calculating the power of electric welding is. There are several gears in the two output, and my calculations seem to be out of order. I think my calculation is wrong. I would like to ask you a complete calculation method of welding power
BX3-500 AC arc welding machine:Maximum output power 380V*95A=36.1KW (only allowed by 35% temporary power) (35% temporary load: 76V500A output current, 10 minutes, 3.5 minutes)Continuous power: 36.1KW*35%=12.64KWAdjustable range of welding: 65V*90A=5.85KW; 76V*500A=37.5KW;
It depends on what type of welding machine, how much current welding, and the length of the welding cable to estimate:1. Commonly known as: AC arc welding arc welding transformer, mainly BX1-500, BX3-500 to 300A; if the current welding, the power consumption per hour is about 8.4 degrees (according to the welding efficiency of 80%, the utilization rate of 70%, the welding voltage 32V calculation);2. SCR rectifier welding: ZX5-500; if the current is welded by 300A, its power consumption per hour is about 8.96 degrees (press welding efficiency 75%, utilization rate 70%, welding voltage 32V calculation);3. Inverter welding machine: ZX7-500: if the current is welded by 300A, the power consumption is about 7.47 degrees per hour (90% of the welder efficiency, 70% of the use rate, and 32V of the welding voltage);The above calculations assume that the length of the welded cable is 0 meters, and the actual power consumption will be greater because of the loss of the welding cable.
Is the output of U2=36V, I2=400A, I1=400*36/440=32.73A of input current, which is 14.4KVA, the number of apparent power, it has the number including power loss, if the efficiency is 0.85, its power is 16.5KW, if the efficiency is 0.95, its power is 15.2KW, if the efficiency is low to 0.6, it the power of 24KW.
