A 36.1 g of iron ore is treated as follows. Theiron in the sample is all converted by a seriesof chemical reactions to Fe2O3. The mass ofFe2O3 is measured to be 12.6 grams. Whatwas the percent iron in the sample of ore?Answer in units of %A 36.1 g of iron ore is treated as follows. Theiron in the sample is all converted by a seriesof chemical reactions to Fe2O3. The mass ofFe2O3 is measured to be 12.6 grams. Whatwas the percent iron in the sample of ore?Answer in units of %
type L COPPER will work or pex lines
I won't tell you the answer, but I'll tell you how to approach this First, find the grams of just iron from Fe2O3. The compound is obviously only a fraction iron, so calculate the amount of iron there is in this. Assuming that this reaction represents perfect reaction conditions and 100% product yield, you can take the amount of iron in grams from Fe2O3 that you found, and then divide it by the weight of the iron ore. You will then get a percentage weight of iron from the original sample of ore. The philosophy is that in a perfect world, the entire iron quantity will be yielded in the product, and so the total iron content found from a product, with known compounds, can be used to calculate % weight of iron from the beginning, where it is just a conglomerate of a bunch of different unidentified elements. Since we know the weight of oxygen and iron and that those are the only two elements in the product, we can calculate backwards from there, whereas the iron ore contains many elements, so we are not able to calculate based on the weight of the ore. If you have any other questions or want me to elaborate further, let me know
type L COPPER will work or pex lines
I won't tell you the answer, but I'll tell you how to approach this First, find the grams of just iron from Fe2O3. The compound is obviously only a fraction iron, so calculate the amount of iron there is in this. Assuming that this reaction represents perfect reaction conditions and 100% product yield, you can take the amount of iron in grams from Fe2O3 that you found, and then divide it by the weight of the iron ore. You will then get a percentage weight of iron from the original sample of ore. The philosophy is that in a perfect world, the entire iron quantity will be yielded in the product, and so the total iron content found from a product, with known compounds, can be used to calculate % weight of iron from the beginning, where it is just a conglomerate of a bunch of different unidentified elements. Since we know the weight of oxygen and iron and that those are the only two elements in the product, we can calculate backwards from there, whereas the iron ore contains many elements, so we are not able to calculate based on the weight of the ore. If you have any other questions or want me to elaborate further, let me know
