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Question:

short-circuit and open circuit transformer question?

Can somebody please help me understand this problem and help me do it? I'm having a hard time with it and help would be greatly appreciated.The following test data were obtained from short-circuit and open-circuit tests of a 50-kVA, 2400-600 V, 60Hz transformer.Voc600V Vsc76.4 VIoc3.34 A Isc 20.8 APoc 484 W Psc 754 WDetermine:A) the equivalent high-side parameters;B) RegulationC)efficiency at rated load and .92 power-factor for lagging.

Answer:

read material regarding transformers Not just once but say 5 times, till you understand what is said. the transformer has copper loss due resistance of primary and secondary. It has additionally iron loss. The equivalent circuit is a sort of representation that brings in these losses. generally you can apply a low voltage to primary till shorted secondary has a current equal to less than rated current. These measurement details are given. Similarly open circuit measurement details are available. With understanding of how the rest can be calculated using worked examples in texts, you can solve it yourself. attempt this See Lee's book on transformers or schaums series on electrical engg.

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