I am confused on the wording of this question and what procedure it wants me to follow. so if anyone could help me that would be great:Copper has a density of 8.94g/cm^3. If a factory has a bar of solid copper that has a mass of 57.0kg and it is drawn into a wire with a diameter of 9.50mm, what length of a wire, in meters, can be produced?Conversion factors that may help (that I know of):1m 10^3mm1m^3 10^6cm^3Please any help is appreciated and please show your thought process if you do the problem out. Thanks in advance!
use density and mass to find volume of copper v m/d use g for mass and then ans is in cm^3 diam of wire gives area of cross section use A pi Xradius^2 and work in cm for radius (0.95/2 cm) vol of wire area x length (57x10^3)/8.94 (cm^3) pi x(0.95/2) x length (in cm) caclulate and change to metres (/100)
The requirements are printed on the master cylinder cap.
I think all thats needed here is to first get the volume of the copper available for the wire. Units must also be consistent Volume of copper 57.0 kg Cu x 1000g/kg x 1cm^3 / 8.94g Cu 6375.8 cm^3 Now the wire is a real long cylinder with a radius of 9.50 mm / 2 4.75mm which is 4.75mm x 1cm / 10mm 0.475 cm Volume of cylinder Area of the base x Height π r^2 H So 6375.8 cm^3 π x 0.475^2 x H H 6375.8 cm^3 / ( π x 0.475^2) cm^2 H 8995 cm to the nearest whole cm 8995cm 8995cm x 1m / 100cm 89.95m So the length of wire produced 89.95m The big thing is to make sure the units are consistent throughout the working.
