We did this experiment in my chemistry class the other day.we had:Solid copper(II)sulfate pentahydrate + fire. What is the product??CuSO4·5H2O(s) + O2(g) --> ????P.S. please balance the equation
This Site Might Help You. RE: Solid Copper(II) sulfate pentahydrate + heat? We did this experiment in my chemistry class the other day. we had: Solid copper(II)sulfate pentahydrate + fire. What is the product? CuSO4·5H2O(s) + O2(g) --> ?? P.S. please balance the equation
How much heat? Simple oven heat will take the pentahydrate water away and turn the copper (II) sulfate from blue to white. The presence of the ligand water bonds have the electrons in the d-orbitals releasing energy seen as blue in the EM spectrum. Without the water the copper (II) sulfate is white. If you added enough heat I imagine you converted the copper sulfate into a copper oxide. At 650 °C, copper(II) sulfate decomposes into copper(II) oxide (CuO) and sulfur trioxide (SO3)
Heating copper sulphate does not result in any reaction with oxygen. The water of crystalisation is driven off and the blue crystaline solid changes int a white powder CuSO4.5H2O →heat→ CuSO4 + 5H2O The loss of water molecules occurs at different temperatures: Copper sulfate loses two water molecules at 63°C, followed by two more at 109°C and the final water molecule at 220°C At 650 °C, copper sulfate decomposes into copper oxide (CuO) and sulfur trioxide (SO3). CuSO4 →heat→ CuO + SO3 At no stage is there any reaction with O2.
