When a solid zinc strip is placed in a blue copper ion solution, the solution turns clear. What happened?a) blue colour was bleached outb) blue ions bonded onto the zinc strip, so the strip became heavierc) blue copper ions were reduced to copper metal, and zinc strip corroded into aqueous ionsd) nothing happenede) the solution would produce electricity until the beaker got too hot to touch...is the answer (c)??
I believe so. It's a redox reaction. a, b, d, and e are out, anyway. Don't forget to eliminate wrong answers from the start!
C Zn + CuSO4> ZnSO4(aq) + Cu(s)
e. an alloy. From Wiki: An alloy is a homogeneous combination of two or greater factors, a minimum of one among this is a metallic, and the place the ensuing cloth has metallic homes. The ensuing metallic substance in many situations has distinctive homes (specially situations significantly distinctive) from those of its aspects.
When a piecec of zinc strip is dipped into a solution containig Cu^2+ ions, the following redox reaction takes place and the deep blue color of the solution because of Cu^2+ ions gradually fades. Zn(s) + Cu^2+(aq) -------> Zn^2+(aq) + Cu(s) In this reaction the zinc rod is eaten away and its shiny silver grey surface is coated with reddish deposit of metallic copper. These changes result from a reaction in which electrons are transferred from zinc atoms to Cu^2+ ions. Metallic zinc loses electrons and dissolves as Zn^2+ ions. Zn(s) -------> Zn^2+(aq) + 2e- Cu^2+ ions present in the solution gain these electrons and are converted to metallic copper. Cu^2+(aq) + 2e- ------> Cu(s) By losing electrons the oxidation number of Zn increases from 0 to +2 and it is said that Zn is oxidized, whereas by gaining electrons the oxidation number of Cu^2+ decreases from +2 to 0 and hence it is said that Cu^2+ is reduced. Zn is the reducing agent and Cu^2+ is the oxidizing agent. The overall reaction is obtained by adding the two half-reactions. Zn(s) -------> Zn^2+(aq) + 2e- Cu^2+(aq) + 2e- ------> Cu(s) --------------------------------------... Zn(s) + Cu^2+(aq) -------> Zn^2+(aq) + Cu(s) As it is explained above, the answer is (c).
