Question:

solve numericals?

A coil of 300 turns is wound uniformly on a ring of non-magnetic material. The ring has a mean circumference of 40 cm and a uniform cross-sectional area of 4 cm2. If the current in the coil is 5A, calculate the magnetic field strength, (b) the flux density and (c) the total magnetic flux in the ring.

Answer:

The ring is very elongated and not circular because the circumference and csa are inconsistent with a circle: radius r circum / 2pi 6.366 cm radius r sqrt (csa / pi) 1.128 cm The general formula for magnetic field strength is B u0*N*I / distance (units of Tesla or Weber per sq m) u0 4pi*10^-7 H/m N 300 turns I 5A distance ? distance 2r for a flat circular coil (b) flux density in Wb/m^2 is the same as field strength in Tesla (c) total flux flux density * csa (would actually be less than this, because B is max at the centre and not constant) Hope this helps

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