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Question:

Heat, vaporization, and melting points of aluminum.?

Some properties of aluminum are summarized in the following list.normal melting point 658°C heat of fusion 3.95 kJ/g normal boiling point 2467°C heat of vaporization 10.52 kJ/g specific heat of the solid 0.902 J/g°C Calculate the quantity of energy required to heat 1.58 mol of aluminum from 33°C to its normal melting point? In KJCalculate the quantity of energy required to melt 1.02 mol of aluminum at 658°C? In KJCalculate the amount of energy required to vaporize 1.02 mol of aluminum at 2467°C? In KJ

Answer:

Calculate the quantity of energy required to heat 1.58 mol of aluminum from 33°C to its normal melting point in KJ- 1.58 mol x 26.98 g/mol x 0.902 J/g°C x (658 - 33)°C x 1 kJ/1000 J = 24.03 kJ Calculate the quantity of energy required to melt 1.02 mol of aluminum at 658°C In KJ- 1.02 mol x 26.98 g/mol x 3.95 kJ/g = 108.7 kJ Calculate the amount of energy required to vaporize 1.02 mol of aluminum at 2467°C In KJ- 1.02 mol x 26.98 g/mol x 10.52 kJ/g = 289.5 kJ

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