I'm a printer, and now I'm experiencing Motor burning problems. Would you like to know if there are any special requirements for stepping motor starting? Will it not start if the load is too large? If the load is too large to start, can the power of the drive be started? Not very understanding, explanation
Therefore, when the stepper motor is started, the pulse frequency of the controller is gradually increased from 0 to the required value of the actual speed. The law of pulse acceleration needs to consider the motor power and load characteristics, the time constant. Can also be determined by actual debugging.
Stepping motor from stationary to some speed needs to be accelerated step by step, or there will be a "no step" phenomenon. The greater the power of the stepper motor, the greater the inertia, so the longer the starting time required.
How do you say that? There are four aspects of stepper motor starting: load, acceleration time, voltage and current, and drive. General internal procedures to compile the printer, it can be out of the acceleration time, voltage and current is relative to the drivers, if you drive and motor can not match each other's words, it is easy to burn, large load can not lead to burn, will only stall, so the load can be excluded so I suggest you check whether the motor driving and matching. As for the large load, the motor can not start, this is related to the voltage and current, the current impact is relatively large, but if the current will lead to the whole machine heating, I do not recommend increasing the current. The most direct way is to change a big torque motor, because the price is not much, convenient and quick. Ha-ha
