Aluminum and bromine react vigorously in a synthesis reactionWhat mass of product can be made by reacting 5.0 g of aluminum and 15 g of bromine?What is the answer and how did you solve the problem?
First write a balanced equation for the reaction: 2Al + 3Br2 → 2AlBr3 2mol Al react with 3 mol Br2 Molar mass Al 27g/mol 5.0g Al 5.0/27 0.185 mol Al This will react with 0.1853/2 0.278 mol Br2 Molar mass Br2 159.8g/mol 15g Br2 15/159.8 0.0939 mol Br2 You have insufficient Br2 which is limiting From the equation: 3mol Br2 will produce 2mol AlBr3 0.0939 mol Br2 will produce 0.09392/3 0.0625 mol AlBr3 Molar mass AlBr3 266.7g/mol 0.0625 mol 0.0625266.7 16.69g of AlBr3 You should round your answer to 2 significant figures - so the correct answer is 17g But your teacher may be happy to accept 16.7 or 16.69g AlBr3 produced.
