Transformer total circuit breaker rated current 380v, rated current 1000a, the rated capacity and output power how to calculate, I did not learn more points
Kva is the unit of apparent power, KW is the unit of active power. Apparent power equal to the root number (active square square + reactive power square)
Kva is apparent power, KW is active power.
inspecting power:
S = 1.732UI = 1.732 × 0.38 × 100 ≈ 65.8 (Kva)
Active power:
P = 1.732UI cosφ = 1.732 × 0.38 × 100 × cosφ
KVA is apparent power, kW is active power.
inspecting power:
S = 1.732UI = 1.732 x 0.38 x 1000 ≈ 658 (kVA)
Active power:
P = 1.732UI cosφ = 1.732 × 0.38 × 100 × 0.8 ≈ 526 (kW)
AC power, power divided into three kinds of power, active power P, reactive power Q and apparent power S, at any time these three power always exist at the same time.
????? The cosine of the phase difference (Φ) between the voltage and the current is called the power factor, denoted by the symbol cosΦ, where the power factor is the ratio of the active power to the apparent power, that is, cosΦ = P / S
????? Three power and power factors cosΦ is a right-angle power triangular relationship: two right-angled edges are active power P, reactive power Q, and oblique edge is apparent power S.
????? S? = P? + Q? S = √ (P? + Q?)
????? Apparent power S = 1.732UI
????? Active power P = 1.732UIcosΦ
????? Reactive power Q = 1.732UIsinΦ
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????? DC = P = UI = U? / R = I?R
