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The mass percent of iron in an iron ore can be determined by converting Fe to Fe2+?

The mass percent of iron in an iron ore can be determined by converting Fe to Fe2+ in acid solution, and then titrating the dissolved sample with KMnO4 solution. A 2.51 g ore sample dissolved in acid required 28.62 mL of 0.0821 M KMnO4 to react the equivalence point. Calculate the mass percent of iron in the ore. 8 H+(aq) + 5 Fe2+(aq) + MnO4-(aq) ----gt; 5 Fe3+ (aq) + Mn2+(aq) + 4 H2O(l) How would you solve this?

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