The relative molecular mass was between 120-150. The testThe organic matter M, which contains only carbon, hydrogen and oxygen, was measured by mass spectrometer. The relative molecular mass was between 120-150. The mass fraction of oxygen element measured by experiment is 48.48%, the ratio of hydrocarbon to mass is 15:2, and only COOH in M molecule is measured by infrared spectrometer. Then the M formula is?
The mass fraction of oxygen element is 48.48%, the mass fraction of hydrocarbon is =51.52%, and the mass ratio is 15:2. The mass fraction of carbon is =51.52%x15/ (15+2) =45.46%, and the mass fraction of hydrogen is =51.52%x2/ (15+2) =6.06%The atomic number of C, H and O is higher than that of =45.46%/12:6.06%/1:48.48%/16=3.79:6.06:3.03Molecules contain only COOH, and oxygen atoms must be even numbers.Therefore, the number of atoms in C, H and O can be reduced to =5:8:4, which may be C5H8O4, and the relative molecular weight is 132
The mass fraction of oxygen element is 48.48%, the mass fraction of hydrocarbon is =51.52%, and the mass ratio is 15:2. The mass fraction of carbon is =51.52%x15/ (15+2) =45.46%, and the mass fraction of hydrogen is =51.52%x2/ (15+2) =6.06%The atomic number of C, H and O is higher than that of =45.46%/12:6.06%/1:48.48%/16=3.79:6.06:3.03Molecules contain only COOH, and oxygen atoms must be even numbers.Therefore, the number of atoms in C, H and O can be reduced to =5:8:4, which may be C5H8O4, and the relative molecular weight is 132
The mass fraction of oxygen element is 48.48%, the mass fraction of hydrocarbon is =51.52%, and the mass ratio is 15:2. The mass fraction of carbon is =51.52%x15/ (15+2) =45.46%, and the mass fraction of hydrogen is =51.52%x2/ (15+2) =6.06%The atomic number of C, H and O is higher than that of =45.46%/12:6.06%/1:48.48%/16=3.79:6.06:3.03Molecules contain only COOH, and oxygen atoms must be even numbers.Therefore, the number of atoms in C, H and O can be reduced to =5:8:4, which may be C5H8O4, and the relative molecular weight is 132
