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Question:

The reaction of powdered aluminum and iron(ll) oxide, 2Al(s) + Fe2O3(s) - Al2O3(s) +2Fe(l), produces so much?

heat the iron that forms is moltenBecause of this, railroads use the reaction to provide molten steel to weld steel rails together when laying trackSuppose that in 1 batch of reactants 4.20mol Al was mixed with 1.75mol Fe2O3.which reactant, if either, was the limiting reactant?calculate the mass of iron(in grams) that can be formed from this mixture of reactants.

Answer:

Paul C is right, but2 - A that's why there are so many different oxidation states in transition metals(but could also be B depending on the element, look at ionization energies) 3 - C that's why they're called inert gases 1 - C because of those full electron cloud it really doesn't like losing electrons 4 - A because of those delocalised electrons from 2 5 - A ceramics tend to be brittle, you can't forge gases
by the equation 2Al(s) + Fe2O3(s) - Al2O3(s) +2Fe(l) 1.75mol Fe2O3 reacts with twice as many moles of Al 3.50 mol Al Al is the excess reagent your first answer is that Fe2O3 is the limiting reagent by the equation 2Al(s) + Fe2O3(s) - Al2O3(s) +2Fe(l) 1.75mol Fe2O3 produces twice as many moles of Fe 3.50 mole Fe using molar mass, find grams 3.50 mole Fe 55.85 g/mol 195.475 grams of Fe your last answer rounded to 3 sig figs is 195 grams of Fe

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