Home > categories > Energy Products > Coke Fuel > The total amount of heat released by the fully burnt 200g coke is 60% by the mass of 10kg water absorption [q coke =3.0 * 107J/kg, C water =4.2 * 103J/ (kg = C)

Question:

The total amount of heat released by the fully burnt 200g coke is 60% by the mass of 10kg water absorption [q coke =3.0 * 107J/kg, C water =4.2 * 103J/ (kg = C)

The total amount of heat released by the fully burnt 200g coke is 60% by mass of 10kg water absorption [q coke =3.0 * 107J/kg, C water =4.2 * 103J/ (kg = C)], q:(1) how much heat is absorbed by water?(2) if the initial temperature of water is 10 degrees C, then, after absorbing heat, the temperature will rise to how much?

Answer:

At a standard atmospheric pressure, the boiling point is 100 DEG C, the temperature of the water rises to a temperature of 100 DEG C, and the temperature will not change,So the water temperature can be increased to 100;Answer: (1) the heat absorbed by water is 3.6 * 106J;(2) after absorbing heat, the temperature of the water will rise to about 100 degrees centigrade

Dry water temperatures:Delta t=Q ceilingC water m water=3.6 x 106J4.2 x 103J/ (kg * c) * 10kgC = 85.7,At the end of a water temperature t=t0+ t=20 C +85.7 =105.7 oc,

(1) the amount of heat released from complete combustion of coke:Q put =mq=0.2kg * 3 * 107J/kg=6 * 106J.Heat absorbed by water:Q =Q * 106J suction ETA =6 * 60%=3.6 * 106J;(2) Q =cm t suction dreams,Dry water temperatures:Delta t=Q ceilingC water m water=3.6 x 106J4.2 x 103J/ (kg * c) * 10kgC = 85.7,