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Question:

Thermodynamic problem?

A well Isolated container contains a mixture of 15 grams ice and 350 grams of water at a temperature of 0 C A 300 gram piece of aluminum is heated to a temperature of 140 C and is then submerged in the water-ice mixtureNo heat enters or leaves the container from the environmentthe specific heat of water is 4180 J/kg Cit takes 3.33x10^5 Joules of heat to melt one kilogram of iceThe specific heat of Aluminum is 900 J/kg C.awhat will be the final temperature of the solution? bActually, although heat may not go into the air, it will go into the containerIf the container is a 600 gram glass cup ( specific heat of glass is 664 J/kg C), the final temperature of the water-aluminum mixture will be lower than what you found in (a)What will be the final temperature?

Answer:

everything settles out at t degreesthe energy to melt the ice (0.015)(3.33 x 10^5) + energy to heat 365 (350 + 15) grams of water to t degrees (0.365)(4180) t the energy that the aluminum gives to the system (0.300)(900)(140-t) 4995 + 1525.7 t 37800 - 270 t 1795.7 t 32805 t 18.3 degrees b) 4995 + 1525.7 t + (0.6)(664) t 37800 - 270 t 2194.1 t 32805 t 15 degrees.

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