A bar of copper with a length of 85.0 cm at a temperature of 620? C is droppedin 200 g of water initially at 75.0? C. The water vaporizes and is converted to steam and theclosed system reaches thermal equilibrium at a final temperature Tf 110? C.a) What is the length of the copper bar at Tf?b) What is the mass of the copper bar?c) Evaluate the change in the entropy ΔS (in J/K given that 1 cal 4.19 J) of the bar of copperas it changes from 620? C to 110? C.d) Evaluate ΔS of the water as it changes from water at 75.0? C into steam at 110? C.e) Deduce ΔS for the system and show that the second law of thermodynamics is not broken.cw 1.0 cal/g.?C, LV 539 cal/g, cst 0.440 cal/g.?C, cCu 0.0923 cal/g.?C, αCu 1.7 x 10-5 /?C.
CBS knows that his character brings in big bucks . Thats what they paid him for and hes been doing it for 30 years . CBS just didnt have the backbone to stand up an admit they were part of the issue .
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I asked something similar earlier, and alot of people gave me hateful answers. BUT. The fact that he called women hoes is not even the problem. It is the fact that he said nappy headed. I didn't even know that was racist. I am white, and my air can be nappy when I don't straighten it out. He was rude and inconsiderate, but I don't think that he was trying to be racist. AND, even if he was, he rags ALL racesunfortuately for him, the race that he ragged that day had ignorant a**holes like Jesse Jackson and Al Sharpton to defend them.
a) ?L L??αCu??T L??αCu?(Tf - T?) L L? + ?L L??(1 + αCu?(Tf - T?)) 85 cm ? (1 + 1.7×10?? °C?? ? (110°C - 620°C)) 84.26 cm b) Heat absorbed by the water is the sum of amount required to heat up liquid from initial temperature to boiling temperature Tb, latent heat of vaporization plus amount to heat up steam from boiling temperature to final temperature: Qw mw ? (cw?(Tb - Ti) + LV + cst?(Tf - Tb)) 200 g ? (1 cal?g???°C???(100°C - 75°C) + 539 cal?g?? + 0.44?g???°C???(110°C - 100°C)) 113680 cal Assuming no heat is lost to surrounding same amount of heat is removed from the copper bar: Qw - QCu mCu?cCu?(T? - Tf) mCu Qw/(cCu?(T? - Tf)) 113680 cal / (0.0923 cal?g???°C???(620°C - 110°C)) 2415 g c) Differential change in entropy equals differential heat transferred divided by thermodynamic temperature (in Kelvins): dSCu dQcu/T (mCu?cCu/T) dT When you integrate this from initial to temperature you get the overall change in entropy: Tf ?SCu ∫ dS ∫ (mCu?cCu/T) dT mCu?cCu?ln(Tf/Ti) Ti 2415 g ? 0.0923 ? cal?g???K?? ? ln( 383 K / 893 K) - 1.669 cal?K?? d) ?SCu mw ? (cw?ln(Tb/Ti) + LV/Tb + cst?ln(Tf/Tb) ) 200 g ? (1 cal?g???°C??? ln(373K / 348K) + (539 cal?g?? / 373K) + 0.44?g???°C???ln(383 K / 373 K) 1.966 cal?K?? e) ?S_system ?SCu + ?Sw - 1.669 cal?K?? + 1.966 cal?K?? 0.297 cal?K?? ?S_system 0, so second law of thermodynamics is not broken.
