how do i solve this?given the 0.05019 EDTA find the volume needed to titratethe Ca and MG in a 0.1414g sample that is 92.5% dolomite CaCO3*MgCO3 (184.44g/mol)2. Ca in 0.201g of CaCO3thanks a lotim so confused on how to do it thanks
mass dolomite 0.1414 x 92.5/1000.1308 g moles dolomite 0.1308 / 184.44 g/mol0.0007091 moles Ca moles Mg 0.0007091 total moles 0.0007091 x2 0.001418 Volume EDTA 0.001418 mol/ 0.05019 M 0.02826 L 28.26 mL moles CaCO3 moles Ca 0.201 g/100.086 g/mol0.00201 moles EDTA V 0.00201/ 0.050190.0400 L 40.0 mL
