Two cylindrical bars, each with diameter of 2.40 cm, are welded together end to end. One of the original bars is copper and is 0.370 m long. The other bar is iron and is 0.185 m long. What is the resistance between the ends of the welded bar at 20°C
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properly the copper welding(brazing) of steel is accepted so of direction the joint could be made however the steel won't have been melted so no longer a real weld as maximum human beings comprehend it.i assume that's to be assumed that the compound bar can income or lose warmth in uncomplicated terms on the loose ends.i do no longer think of i will bypass futher with out understanding the particular warmth of the two components(thank god for that; that's sums returned).
I answered a question like this earlier today You are going to use the equation RpL/A p is the resistivity of the metals p (iron) 1*10^-7 p (copper) 1.724*10^-8 L is the length of each bar A is the area of each bar and it is taken as a cross section The equation for the area will be A (3.14)r^2 They give you the diameter so you have to divide by 2 to get the radius also you have to change the radius from cm to m R(iron) 1*10^-7 * (.185 m)/ (3.14 * .012^2) R(copper) 1.724*10^-8 * (.370 m)/ (3.14 * .012^2) R (iron) 4.089*10^-5 R (copper) 1.41*10^-5 Since the two bars are next to each other this is considered a series thus you add the resistance together R R(iron) + R(copper) 5.499*10^-5 ohms
