UPS battery pack maintenance time calculation?
Seeking time to maintain. S = C ÷ I = battery capacity ÷ output current 200 (ah) ÷ 39.0625 (A) = 5.12 (hours).
Seek input 7.5KW, the battery output current. 16 series in series for the 192 volts, two groups in parallel for the 200ah, then the input DC current is: I = P ÷ V = 7.5 (KW) ÷ 192 (V) = 0.0390625 (thousand) = 39.0625A
Find the total power that the input needs to enter. High power UPS efficiency of 80%, total power = load power ÷ 80% = 6 (KW) ÷ 80% = 7.5 (KW)
