A 4400 watt motor is located 930 feet away from the 240v source. The motor's minimum voltage is 220 volts. What size of wire is required to maintain at least 220v at the pump? How much power is lost with this size wire?Please help! Thanks!
this has to be a theoretical calculation, because you can't do this in real life. For one thing, the startup surge of the motor will lower the voltage so much it won't start. And electrical codes won't allow this either. 4400/220 20 amps. R 20v/20a 1 ohm there are two wires, so length is 2x930 1860 ft at 1860 ft, this is 0.538 ohms per 1000 ft looking at the wire gauge tables, #7 wire is 0.498 ohms/1000 ft #8 wire is 0.628 ohms/1000 ft use #7 wire you will have 0.926 ohms for 930 ft (x2) at 20 amps that is E IR 18.5 volts lost P 20*18.5 370 watts. .
enable's presume you will use as much as 50 amps of contemporary. 25a on line A, 25a on line B. each and each line offering 120vac on the source. you do no longer elect below 114vac on the barn, so your drop is 6 volts. Ohm's regulation states Voltage contemporary x Resistance. you are going to be able to desire to locate the optimum resistance which may well be tolerated. 6volts 25a x Resistance 6/25 .25 ohms max over that distance. What length twine is .25 ohms or much less over 250 ft? that could desire to be 10ga twine. i could bypass with 8ga to furnish much less voltage drop. 10ga twine has a million ohm consistent with a million,000 ft .25 ohms over 250 ft which meets the minimum standards. there's a right away bury cable that would not require conduit encasement.
