i need to have an immediate answer (solution to this) thanks:Determine the transformer bridge rectifier and filter capacitorspecifications/values required to produced an output current of 3A and a nominaloutput voltage of 17VDC with a ripple voltage of 2 Vpp. Assume a line voltage(from Meralco) of 220VAC, and that the design is to use a center-tappedtransformer.2. Given the characteristics of the raw DC supply just designed, determine thecomponent values of a transistor regulator circuit (based on “Simple TransistorVoltage Regulator Circuit” from the CCS1
If you want to step 12 volts AC to 96 AC, you need a transformer with a primary to secondary winding ratio of 8. You then connect the 12 volts to the secondary, and will get 96V at the output. The most accurate way to do this, is go to a transformer shop and ask them to do this. They will ask you for current requirements. If this is not an option, go to a hardware store and ask for a 120V to 15V (or whatever value is closest) transformer. Keep in mind that while voltage is multiplied, current is divided, so that at the end you get the same power. So, if you have a transformer with n8: V12*896 volts I 110/813.75 amps
If you are to use a center-tapped transformer, you don't need a bridge rectifier; a pair of diodes will do the job. The output voltage will need to be about 13.5 vrms each side of the center tap; this will deliver 19 volts p-p, the rectifier will eat 0.75 volts, the ripple will amount to one more, and you'll have your 17 vDC. Since the filter capacitor will be working into a load of 17/3 ohms, and the voltage decay is to be no more than 2/17 of the output, you can use the exponential decay equation to figure the necessary time constant, and use the load resistance to get the capacitance. (You can punch a calculator as well as I can.) 2: The regulator transistor will be burning five volts at three amps, or 15 watts dissipation. A TO-3 may be satisfactory in this application, but it will be a close call. The rest of the component values can be determined using Ohm's law.
