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Question:

What determines if brackets or parenthesis are used in a inequality?

for example (9x+1) (5-10x)0 the answer is 1/9 , .5 but i dont know hot to correctly write the answer with brackets, parenthesis or both? what determines which 1 you use?

Answer:

There is really no set rule as they mean the same thing, do what is inside first. In general parenthesis come first and then if you need to group more together you use brackets and then if there is still more you use the squiggly brackets {}. What you have is the standard format since you have the 9x+1 as one group and 5-10x as the second group. You can actually just use parenthesis for everything, but it becomes difficult to read, which is the reason the others are used. ((((10+1)+5)-2)+6) is awkward to read but {[(10+1)+5]-2} it is easier to see what to start with and what to work out to.
Please read all, because i think it's supposed to be -(1/9) Squiggly Brackets are for solution sets. {x:x1/9 or x0.5} Parenthesis (), if you mean like (1/9,0.5), means all the numbers between 1/9 and 0.5 BUT NOT including 1/9 or 0.5. Brackets [], [1/9,0.5], means all the numbers between 1/9 and 0.5, and INCLUDING 1/9 and 0.5. (9x+1)(5-10x)0 (9x+1)*5*(1-2x)0 (9x+1)(1-2x)0 9x - 18x^2 + 1 - 2x 0 -18x^2 + 7x + 1 0 (9x+1)(-2x+1) 0 9x+1 0 . -2x+1 0 x -(1/9) . x 1/2 ****I did it out anywayI think you are missing a negative sign next to your 1/9**** But anyway, since and are not including, you would use soft brackets, known as the parenthesis (). So the solution is (-(1/9),1/2) It's best to stick to either fractions or decimals. NOT good to use both. c:

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