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What is the empirical formula for a compound of aluminum.Chemistry, please help?

I have absolutely no idea how to do thisIf you could just explain to me how to do it, that would be wonderful.What is the empirical formula for a compound of aluminum and fluorine that is 32% aluminum and 68% fluorine?The answer is AlF3 (3 is the subcript), but I just don't know how to get the answerI found the answer somewhere and I've done everything I can think of, but I never get the answerI'm positive that's the answer, tooThank you for all answersAlso, if someone could explain this one, too, that'd be great.What is the empirical formula for a compound that is 26.56% potassium, 35.41% chromium, and 38.03% oxygen? The answer is K2Cr2O7Thanks.

Answer:

Foods that are: low in cholesterol low in saturated fat high in momounsaturated fat high in polyunsaturated fat high in fiber high in omega 3 oils Eat things like more fruits and veggies, oatmeal, skinless chicken breasts, low fat cuts of meat or cold cuts (such as Boar's Head sliced at the deli counter, and not packages of Oscar Meyer bologna), fish like salmon, sardines, tuna fish, Smart Balance spread, olive oil, beans and legumes, salad with vinagrette dressings instead of creamy dressings like ranch, creamy italian, or caesar.(a basic vinagrette is one part your favorite flavored vinegar to three parts olive oilBalsamic vinegar is fantastic for this, plus salt and pepper to tasteAdd a teaspoon or two of some good dijon mustard to keep it emulsified, and shake well.) Good luck!
High Triglycerides mean you are eating too many carbohydrates (bread, potatoes, pasta, white rice, sugar and high fructose corn syrup) Reduce the carbohydrates and stay away from the bad fats like trans fat (hydrogenated or partially hydrogenated fats)I would increase the healthy fats in your diet like butter, coconut oil, olive oil, cod liver oil)
Natural Cholesterol Guide
Instead of each element being out of 100%, assume that the sample is 100 gBy doing this, you can change the percent of each element to g 32% Al is 32 g 68% F is 68 g Use the average atomic mass of Al and F to convert grams of given (originally percent) to moles Al: 32 g x (1 mol/27 g) 1.19 moles Al F: 68 g x (1 mole/19 g) 3.58 moles F Divide both answers by the lower answer to get whole numbers for the mole subscripts: Al: 1.19/1.19 1 F: 3.58/1.19 3 These are the mole coefficients that are in the formula you found AlF3 Other question you asked: (again assume 100 g and use averge atomic mass of each element) K: 26.56 g x (1 mole/39 g) 0.68 mole K Cr: 35.41 g x (1 mole/52 g) 0.68 mole Cr O: 38.03 g x (1 mole/16 g) 2.38 mole O Divide each mole by lowest answer: 0.68/0.68 1 K 0.68/0.68 1 Cr 2.38/0.68 3.5 O Since 3.5 is between 3 and 4 it's hard to decide which to round up or down to get a whole number so instead multiple all 3 values by 2 to get a whole number for 3.5: K: 1 x 2 2 K Cr: 1 x 2 2 Cr O: 3.5 x 2 7 O These are the mole subscripts you found in your formula: K2Cr2O7

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