Two blocks are placed in thermal contactOne block is aluminum (specific heat.900 J/gK) with the mass of 200g with an initial tempof 80.0 degrees CelsiusThe second block is iron (s.h..450 J/gK) with a mass of 100g with an initial tempof 40.0 degrees CelsiusWhat is the final temperature after thermal equilibrium is achieved? That is the whole problemAny help is appreciated!
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In a problem like this you need to remember that any heat lost from one block is equal to the heat gained by the other (and vice versa), therefore this problem can be setup like this: q(Al) + q(Fe) 0 - q(Al) - q(Fe) Where q(Al) is any heat gain or lost by Aluminum, and q(Fe) is the heat gained or lost by Iron Now lets expand that equation by plugging in the information we know: q(Al) Mass Al Specific Heat Al Delta T q(Fe) Mass Fe Specific Heat Fe Delta T q(Al) - q(Fe) 200g 0.900 J/gC (Tf - 80C) - 100g 0.450J/gC (Tf -40C) We know that the Tf (Final Temp) of both will be the same since the problem says they reach thermal equilibriumWe can change the specific heat values to J/gC since a change in one degree C is the same as a change of 1 K Now we solve for Tf I will leave the algebra to you for practice, but going through it quickly I got a Tf of 72C Work through the problem and see if you get the same answerHope that clarifies things for you.
