a 500 gram iron ore sample was determined to contain 242 grams of Iorn. what is the Mass percent of Iron in the Ore?
You made a small error somewhere in your calculation. The layout is OK but.242 x 100 24,200. 24,200 / 500 48.4 To find the mass %. Simply divide the determined mass (242g) of Iron by the mass of the Ore (500g) and multiply by 100. (500g 100%) (242g / 500g) x 100 48.40% of Iron by mass
neither, both damage your hair in the long run!(i should know i'm a hairdresser)!! but if you absolutly need 1 then ceramic is better.
I have a ceramic hair straightener and it works perfectly and I have very curly hair. :P Also don't bother buying a straightener under 200 they're crap and not worth the money, your best bet is to purchase one from a salon. It's worth it believe me!
% via mass of Fe2O3 (mass of organic Fe2O3 / mass of iron ore) x one hundred% mass of Fe2O3 (organic) (mass of iron produced / MW of iron) x ( stoichiometric mole ratio of Fe2O3 over Fe based on the given chemical reaction x MW of Fe2O3 mass of iron produced 453 g MW of Fe fifty 5.eighty 5 stoichiometric mole ratio of Fe2O3/Fe a million/2 MW of Fe2O3 159.7 mass of organic Fe2O3 (453/fifty 5.eighty 5) x (a million/2) x 159.7 mass of organic Fe2O3 647.sixty six grams %via mass of Fe2O3 (647.sixty six / 752) x one hundred 86.13 %
neither, both damage your hair in the long run!(i should know i'm a hairdresser)!! but if you absolutly need 1 then ceramic is better.
I have a ceramic hair straightener and it works perfectly and I have very curly hair. :P Also don't bother buying a straightener under 200 they're crap and not worth the money, your best bet is to purchase one from a salon. It's worth it believe me!
% via mass of Fe2O3 (mass of organic Fe2O3 / mass of iron ore) x one hundred% mass of Fe2O3 (organic) (mass of iron produced / MW of iron) x ( stoichiometric mole ratio of Fe2O3 over Fe based on the given chemical reaction x MW of Fe2O3 mass of iron produced 453 g MW of Fe fifty 5.eighty 5 stoichiometric mole ratio of Fe2O3/Fe a million/2 MW of Fe2O3 159.7 mass of organic Fe2O3 (453/fifty 5.eighty 5) x (a million/2) x 159.7 mass of organic Fe2O3 647.sixty six grams %via mass of Fe2O3 (647.sixty six / 752) x one hundred 86.13 %
You made a small error somewhere in your calculation. The layout is OK but.242 x 100 24,200. 24,200 / 500 48.4 To find the mass %. Simply divide the determined mass (242g) of Iron by the mass of the Ore (500g) and multiply by 100. (500g 100%) (242g / 500g) x 100 48.40% of Iron by mass
