What is the percentage of CaCO3 in the original sample?What is the percentage of MgCO3 in the original sampleI found the mass‘s but I cannot get wiley to accept my %‘sDolomite is a mineral consisting of calcium carbonate (CaCO3) and magnesium carbonate (MgCO3). When dolomite is strongly heated, its carbonates decompose to their oxides (CaO and MgO) and carbon dioxide is expelled. When a 91.6 g sample of dolomite was strongly heated, a residue of mass 47.6 g remained.
The % of CO2 lost from the dolomite is a WEIGHTED AVERAGE of the % of CO2 lost from CaCO3 and MgCO3 when they are heated % of CO2 lost from sample 44/91.6 x 100% 48.0% % of CO2 lost from CaCO3 when heated 44 / 100 44% % of CO2 lost from MgCO3 when heated 44/ 84 x 100 52.4% Call the percentages of CaCO3 and MgCO3 C and M respectively Then 52.4M + 44C 100 x 48 4800 we also know M + C 100 ( x 44 to eliminate C then subtract) 44M + 44C 4400 From these two linear equations we can calculate that :- 8.4 M 400 M 45% so C 55% Dolomite sample is 55% CaCO3 and 45% MgCO3
