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Question:

What is the radius of the silo, correct to the nearest tenth of a foot?

A graphing calculator is recommended.A grain silo consists of a cylindrical main section and a hemispherical roof. If the total volume of the silo (including the part inside the roof section) is 16,000 ft^3 and the cylindrical part is 30 ft tall, what is the radius of the silo, correct to the nearest tenth of a foot?r = ( ) ft?

Answer:

portion of circle = ?(r)^2 subsequently, the radius is 5, so we purely plug in r for 5. A = ?(5)^2 A = 25? ? is approximately 3.1416, so we are able to plug in that for ? A = 25(3.1416) *makes use of calculator* A = seventy 8.fifty 4, which rounds to seventy 8.5, determination C.
Formula for the volume of a cylinder. volume = pi*r^2*h Then we input the knowns: 16000 = pi * r^2 * 30 r = (16000/(pi*30))^1/2 Then solve for r: r = (40 *3^(1/2))/(3*pi^(1/2)) = 13.029 Hope this helps.

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