What is the relationship between capacitance and voltage?
when you charge 5v, want to be in the first The capacitor is full, the second capacitor half; if you charge a higher voltage 6v, then the first capacitor to diffuse out, the actual performance of the capacitor was breakdown!
In your case, you can think of two capacitors as two containers, 5v capacity than 10v half (because they are 0.01uF),
The larger the capacity of the capacitor, the larger the voltage, the smaller the capacity (uF). Since q = Cu, q is the current charge number of the capacitor, which is substantially proportional to the volume of the capacitor
