A 55.0-g piece of copper wire is heated, and the temperature of the wire changes from 19.0 degrees C to 86.0 degrees C. The amount of heat absorbed is 343 cal. What is the specific heat of copper?Thank you so much for your help!
Q=m*Cp*deltaT Q=heat gained by copper wire (J) ==== 343 cal * 4.18400 J/Cal = 1435.112 J m=mass of copper (Kg) ============ .050 Kg Cp= specific heat capacity J/Kg*C === Unknown deltaT=temperature difference ====== (86C - 19C) = 67C So... Isolate Cp Cp = Q/(m*deltaT) Cp = 1435.112/(.050*67) Cp = 428.4 J/Kg*C Check: Is roughly what my engineering textbook gives me (ASHRAE fundamentals chapter 39)
