A typical machine tests the tensile strength of a sheet of material cut into a standard size of 5.00 centimeters wide by 10.0 centimeters longThe machine consists of one clamp that holds the entire width (5.00 centimeters) so that it hangs verticallyA second clamp is placed on the lower end of the object, to which a variable downward force is appliedThe force is slowly increased until the object ruptures, and the breaking force is recorded.A strip of aluminum foil with a thickness of 15.0 micrometers and matching the size recommendations of the machine is placed in the machine and testedThe force needed to rupture the foil is found to be 233 newtons.
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According to my research, the tensile strength of metals such as aluminium is reported as MPaThis would translate to MN/m? Your sample has a width of 5.0cm 0.05m and a thickness of 15?m or 1510^-6m The force required to break the foil is 233N Tensile strength 233/ (0.051510^-6) Tensile strength 310,666,667Pa OR tensile strength 310.7MPa
