A long thin solenoid has 460 loops of wire per meter, and a 28-A current flows through the wire. If the permeability of the iron is 3000u (mu_0) , what is the total magnetic field inside the solenoid?(answer in Teslas)I have tried this problem and am struggling to find the correct answer. PLEASE HELP!Thanks A Million
the magnetic field in a solenoid in free space is B mu x current x loops per meter (you've probably derived this equation in class). if you have other materials than free space basically just replace mu, the permeability of free space, with the new permeability so the answer is B (3000 x mu_0) x 28 x 460 remember mu_0 is the permeability of free space which is a constant. so basically the answer is to multiply everything together :P
No of turns2500x20/a hundred500turns Flux 500x present day/reluctance Reluctance length/(areax4pix10^ -7) 0.2/(4pi^2x(0.a million/2)^2)2x10^7. InductanceN^2/(2x10^7)0.0125 henries capability savedIntegeral(Ldi/dtXi)xdt(0.0125)x1 watts
